Question

lcm of 2x^2-5x-3,4x^2-36​

Answer 1

Answer:

$\bf{\text{L.C.M}=4(2x+1)(x^2-9)}$

Step-by-step explanation:

I have found the L.C.M by factorization

$2x^2-5x-3$

$=2x^2-6x+x-3$

$=2x(x-3)+1(x-3)$

$=(2x+1)(x-3)$

$4x^2-36$

$=4(x^2-9)$

$=4(x^2-3^3)$

$=2^2(x-3)(x+3)$

$\text{L.C.M}=2^2(2x+1)(x-3)(x-3)$

$\bf{\text{L.C.M}=4(2x+1)(x^2-9)}$

Answer 2

Answer:

Step-by-step explanation:

I have found the L.C.M by factorization