Question

lcm of f(x)=20x(2x²+3x-2)​

Answer 1

Step-by-step explanation:

Let f(x)= 2x

2

−3x−2

g(x)= (x−2)(x+1)

Factor of 2x

2

−3x−2=(2x+1)(x−2)

So, H.C.F = (x−2)

L.C.M = (x−2)(2x+1)(x+1)

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