LCM of n2-2x-24 and k2-kx-6 is (x-6) find k a) 3 b) 5 c) 6 d) 8
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Answer:
Given that (x−6) is the HCF of
x
2
−2x−2y and x
2
−4x−6(x−6) is factor of both expression
Let f(x
1
)=x
1
2
−2x
1
−24
and f(x
2
)=x
2
2
−4x
2
−6
Now f(x
1
)=f(x
2
) at (x
1
=x
2
=6)
⇒(6)
2
−2(6)−24=(6)
2
−4(6)−6
⇒0=30−6k⇒6k=30∴k=5
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