Math, asked by nasreenkhatoon265, 5 days ago

LCM of the following 12,23,7,9,17,50​

Answers

Answered by priya221612
4

Answer:

LCM (8, 12) = 24

(1) 12, 15 and 21

The prime factors of the given numbers are

12 = 2 x 2 x 3 = 2² × 3¹

15 = 3 x 5 =3¹ × 5¹

21 = 3 x 7 =3¹ × 7¹

HCF of 12, 15 and 21

HCF of (12, 15 & 21) = 3

LCM of 12, 15 and 21

LCM of (12, 15 & 21) = 2² × 2¹ × 5¹ × 3¹ × 7¹

LCM of (12, 15 & 21) = 420

(2) 17, 23 and 29

The prime factors of the given numbers are

17 = 1 x 17

23 = 1 x 23

29 = 1 x 29

HCF of 17, 23 and 29

HCF of (17, 23 & 29) = 1

LCM of 17, 23 and 29

LCM of 17, 23 and 29 = 23 x 29 x 1 x 17

LCM of (17, 23 & 29) = 11339

(3) 8, 9 and 25

The prime factors of the given numbers are

8 = 2 x 2 x2

8 = 2³

9 = 3 x 3

9 = 3²

25 = 5 x 5

25 = 5²

HCF of 8, 9 and 25

HCF of (8, 9 & 25) = 1

LCM of 8, 9 and 25

LCM of (8, 9 & 25) = 2 x 2 x2 × 3 x 3 × 5 x 5

LCM of (8, 9 & 25) = 1800.

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Answered by peermohamed54362
1

Answer-

16,422

Step-by-step explanation:

2*3*2*23*7*3*17 is 16,422

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The number of ordered triplets `(a, b, c)` such that `L.C.M.(a, b) = 1000, L.C.M. (b,c) = 2000 and L.C.M. (c,a) = 2000`

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