LCM of two number P and Q is 2448. HCF of P and Q is a perfect square. Difference between P and Q is same as their HCF. What is the sum of P and Q?
Answers
Given :
LCM of p and q = 2448
HCF of p and q = p - q
We know that
LCM × HCF = pq
==> HCF = ( pq) /2448
==> p - q = (pq)/ 2448
2448
= 2× 2× 2 × 2× 3 × 3 × 17
Since p - q is a perfect square,
We can find the product pq such a way that it contains all the factors of 2448 and a perfect square.
p = 153 & q = 144
Now,
p + q = 153 + 144 = 297
I hope this answer helps you
Answer:
Assume that p>q.
Assume that p>q.Given :
Assume that p>q.Given :LCM of p and q = 2448 HCF of p and q =p - q
Assume that p>q.Given :LCM of p and q = 2448 HCF of p and q =p - qWe know that
Assume that p>q.Given :LCM of p and q = 2448 HCF of p and q =p - qWe know thatLCM x HCF = pa
Assume that p>q.Given :LCM of p and q = 2448 HCF of p and q =p - qWe know thatLCM x HCF = pa==> HCF = ( pg) /2448
Assume that p>q.Given :LCM of p and q = 2448 HCF of p and q =p - qWe know thatLCM x HCF = pa==> HCF = ( pg) /2448==> p - q = (pq)/ 2448
Assume that p>q.Given :LCM of p and q = 2448 HCF of p and q =p - qWe know thatLCM x HCF = pa==> HCF = ( pg) /2448==> p - q = (pq)/ 24482448
Assume that p>q.Given :LCM of p and q = 2448 HCF of p and q =p - qWe know thatLCM x HCF = pa==> HCF = ( pg) /2448==> p - q = (pq)/ 24482448= 2x 2x 2 x 2x 3 x 3 x 17
Assume that p>q.Given :LCM of p and q = 2448 HCF of p and q =p - qWe know thatLCM x HCF = pa==> HCF = ( pg) /2448==> p - q = (pq)/ 24482448= 2x 2x 2 x 2x 3 x 3 x 17Since p - q is a perfect square,
Assume that p>q.Given :LCM of p and q = 2448 HCF of p and q =p - qWe know thatLCM x HCF = pa==> HCF = ( pg) /2448==> p - q = (pq)/ 24482448= 2x 2x 2 x 2x 3 x 3 x 17Since p - q is a perfect square,We can find the product pq such a way that it contains all the factors of 2448 and a perfect
Assume that p>q.Given :LCM of p and q = 2448 HCF of p and q =p - qWe know thatLCM x HCF = pa==> HCF = ( pg) /2448==> p - q = (pq)/ 24482448= 2x 2x 2 x 2x 3 x 3 x 17Since p - q is a perfect square,We can find the product pq such a way that it contains all the factors of 2448 and a perfectsquare.
Assume that p>q.Given :LCM of p and q = 2448 HCF of p and q =p - qWe know thatLCM x HCF = pa==> HCF = ( pg) /2448==> p - q = (pq)/ 24482448= 2x 2x 2 x 2x 3 x 3 x 17Since p - q is a perfect square,We can find the product pq such a way that it contains all the factors of 2448 and a perfectsquare.p = 153 & q = 144
Assume that p>q.Given :LCM of p and q = 2448 HCF of p and q =p - qWe know thatLCM x HCF = pa==> HCF = ( pg) /2448==> p - q = (pq)/ 24482448= 2x 2x 2 x 2x 3 x 3 x 17Since p - q is a perfect square,We can find the product pq such a way that it contains all the factors of 2448 and a perfectsquare.p = 153 & q = 144Now,
Assume that p>q.Given :LCM of p and q = 2448 HCF of p and q =p - qWe know thatLCM x HCF = pa==> HCF = ( pg) /2448==> p - q = (pq)/ 24482448= 2x 2x 2 x 2x 3 x 3 x 17Since p - q is a perfect square,We can find the product pq such a way that it contains all the factors of 2448 and a perfectsquare.p = 153 & q = 144Now,p +q = 153 + 144 = 297
Assume that p>q.Given :LCM of p and q = 2448 HCF of p and q =p - qWe know thatLCM x HCF = pa==> HCF = ( pg) /2448==> p - q = (pq)/ 24482448= 2x 2x 2 x 2x 3 x 3 x 17Since p - q is a perfect square,We can find the product pq such a way that it contains all the factors of 2448 and a perfectsquare.p = 153 & q = 144Now,p +q = 153 + 144 = 297I hope this answer helps you