LCM of two numbers is 14 times their HCF if sum of HCF and LCM is 601 of one of the number is 80 find the other number
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Let the other number be
′
x
′
Given:LCM+HCF=600
⇒14HCF+HCF=600
⇒15HCF=600
⇒HCF=40
⇒LCM=14×40=560
Since HCFxLCM=Product of 2 numbers
=>40×560 = 280×x
⇒x=
280
40×560
⇒x=40×2
⇒x=80
hence the other number is 80.
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