Question

LCM of two numbers is 2295 and HCF is 9. If one of the numbers is 153, find the other number

Answer 1

Heya user,
Here's your answer.


We know that product of two numbers = product of their LCM and HCF

Given, one number x = 153
let the other number be y
LCM (x,y) = 2295
HCF(x,y) = 9


Substituting the values, we get

2295*9 = y*153

$y = \frac{2295*9}{153}$

y = 135

Therefore, the required answer is 135.
Hope it helped.
Regards.

Answer 2

Solution :

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Given :

LCM of two numbers is 2295,

HCF of the two numbers is 9,.

&

One of the number is 153
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To Find :

The other number,.

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Let the other number be y,.

We know that,

LCM × HCF = Product of the number,.

Hence,

⇒ 2295 × 9 = 153 × y

⇒ 20655 = 153y

⇒ y = $\frac{20655}{153}$

⇒ y = 135

∴ The other number is 135,.

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                                       Hope it Helps !!