Question

Lcm of two prime number x and y (x>y) is 161 then the value of 3y-x is

Answer 1

 H. C. F of two prime numbers is 1.  Product of numbers = 1 x 161 = 161.

 Let the numbers be a and b . Then , ab= 161.

 Now, co-primes with  product 161 are (1, 161) and (7, 23).

 Since x and y are prime numbers and x >y , we have x=23 and y=7.

 Therefore,  3y-x = (3 x 7)-23 = -2

hope this helps you out!

Answer 2

Answer:

-2

Step-by-step explanation:

x * y = LCM * HCF

HCF of two prime numbers = 1

x * y = 161 * 1

x * y = 161

x * y = 7 * 23

x>y this condition => 23 > 7

so, x = 23, y = 7

=> 3y - x

=> 3(7) - 23

=> 21 - 23

=> -2