Question

LCM of x²-1 and x+1​

Answer 1

Answer:

x+1 is lcm of given values

Step-by-step explanation:

LCM (x+1)(x-1) and (x+1)

so the common one is x+1

so;the LCM is x+1

may I correct

Answer 2

Given:

First expression is,

${x}^{2} - 1$

=(x-1) (x+1)

Second expression is,

$x + 1$

Solution:

Common expression is (x+1)

Remaining expression is (x-1)

Therefore, L.C.M of x²-1 and x+1 = Common expression and remaining expression=(x+1) (x-1).