Question

Lcm os two number is 162their hcf is27 and one of the number is 81 .what us the other number

Answer 1

Step-by-step explanation:

Lcm and hcf of the numbers are :162and 27 . the first number given=81 so the other number = (LCM×HCF)/the first number. hence the second number=. (162×27)÷81= 54

Answer 2

Given:

L.C.M. of two numbers = 162.

H.C.F. of two numbers = 27.

One of the number is = 81.

To find:

The other number.

Solution:

L.C.M. of two numbers = 162.

H.C.F. of two numbers = 27.

One of the number is = 81.

Let, the other number be, 'n'.

We know that, the product of the L.C.M. and H.C.F. of two numbers = Product of the two numbers.

∴ According to the problem:

(81 × n) = (162×27)

⇒ 81n = 4374

⇒ n = (4374 ÷ 81)

⇒ n = 54.

∴ The other number is 54.

Answer:

               The other number is 54.