LCM (p, q) × HCF (p, q) = pq
Answers
Answered by
4
Heyy...
Step-by-step explanation:
P=a²b³
q=a³b
HCF (p,q) =a²b
LCM (p.q)=a³b³
As we know that HCF(p,q)xLCM(p,q)=a²bxa³b³
=a⁵b⁴ ---------- equation 1
pq=a²b³xa³b
=a⁵b⁴-----------equation 2
from 1 and 2
we can say that HCF(p,q)xLCM(p,q)=pq
Hope this helps
Answered by
2
The multiple of LCM and HCF of two numbers is equal to the product of two numbers.
Given:
For proofing the given relation, Let us consider two numbers be 6 and 8.
The Product of two numbers is
Factors of 6 and 8 is,
Hence,
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