LDBC=70° and LCAB=30° find LBCD
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Given:-
- ∠DBC = 70°
- ∠CAB = 30°
To find:-
- ∠BCD
Answer:-
We know that angles in the same segment are equal.
So, ∠DAC = ∠DBC
→ ∠DAC = 70°
Now, we know that, the opposite angles in a cyclic quadrilateral are supplementary, that is, their sum is 180°
So, ∠DAB + ∠BCD = 180°
→ ∠DAC + ∠CAB + ∠BCD = 180°
→ 70° + 30° + ∠BCD = 180°
→ 100° + ∠BCD = 180°
→ ∠BCD = 180° - 100°
→ ∠BCD = 80° Ans
Extra knowledge:-
- Two circles are congruent only if their radii are equal
- Equal chords of a circle subtend equal angles at the centre.
- If two arcs are congruent, the corresponding chords are equal.
- The perpendicular from the centre of the circle bisects the chord.
- Equal chords of a circle are equidistant from the centre.
- The angle subtended by an arc of a circle is double the angle subtended by it at any point on the remaining part of the circle.
- The angle in a semicircle is 90°.
- The opposite angles of a cyclic quadrilateral are supplementary.
- If one side of a cyclic quadrilateral is produced, then the exterior angle so formed is equal to the interior opposite angle.
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