Question

le 17.10. A packet is dropped from a balloon which is going upwards with a velocin
Tate the velocity of the packet after 2 seconds.
on. Given : Velocity of balloon when the packet is dropped (u) =-12 m/s (Minus sign​

Answer 1

Answer:

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Answer 2

Answer :

➥ The velocity of the packet after 2 sec = -31.6 m/s

Given :

➤ Intial velocity of the balloon (u) = -12 m/s

➤ Acceleration due to gravity (a) = -9.8 m/s²

➤ Time taken (t) = 2 sec

To Find :

➤ The velocity of the packet (v) = ?

Solution :

The velocity of the packet after 2 sec

From first equation of motion

⟾ v = u + at

⟾ v = -12 + (-9.8) × 2

⟾ v = -12 - 9.8 × 2

⟾ v = -12 - 19.6

⟾ v = -31.6

Hence, the velocity of the packet after 2 sec is -31.6 m/s.

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Some related equations :

⪼ s = ut + ½ at²

⪼ v = u + at

⪼ v² = u² + 2as