Math, asked by riyaajha225, 2 days ago

le 4: The perimeter of a rectangular field is 42m 28cm. The ratio of its length and breath is 5:2. Find the dimensions of the field.
Please explain ( :

Answers

Answered by snehitha2
16

Answer:

The length of the rectangular field is 15.1 m and breadth is 6.04 m

Step-by-step explanation:

Given :

The perimeter of a rectangular field is 42m 28cm.

The ratio of its length and breadth is 5:2

To find :

the dimensions of the field.

Solution :

The ratio of length and breadth is 5 : 2.

Let the length of the field be 5x and breadth be 2x.

The perimeter of the rectangular field

= 42 m 28 cm

= 42 m + 28 cm

= 42 m + 0.28 m ( 1 cm = 0.01 m )

= 42.28 m

We know,

Perimeter of the rectangle = 2(length + breadth)

42.28 = 2(5x + 2x)

42.28/2 = 7x

7x = 21.14

x = 21.14/7

x = 3.02

Length :

= 5(3.02)

= 15.1 m

Breadth :

= 2(3.02)

= 6.04 m

Therefore, the length of the rectangular field is 15.1 m and breadth is 6.04 m.

Answered by spbankingandsscserie
24

Length = 1510 cm

Breadth = 604 cm

Question -:

The perimeter of a rectangular field is 42m,28cm. The ratio of its length and breath is 5:2. Find the dimensions of the field.

Explanation -:

Given :

  • Perimeter of a rectangular field = 42m,28cm
  • Ratio of length and breadth = 5 : 2

To Find :

  • Length and breadth of the rectangular field

Solution :

Ratio of length and breadth = 5 : 2

Let us assume the length as '5x' and breadth as '2x'

Perimeter of a rectangular field = 42m,28cm

42m + 28 cm

→ 4200cm + 28 cm (1 m = 100 cm)

→ (4200 + 28) cm

→ 4228 cm

Perimeter = 4228 cm

First we will calculate the length and breadth of the rectangular field

We know,

 \star \: \small\boxed{ \rm{ Perimeter \:  of  \: a  \: rectangle = 2(Length + Breadth)}}

On substituting the values we get

 \small\sf{ 4228 = 2(5x + 2x)}

 \rightarrow \small\sf{4228 = 2(7x)}

 \rightarrow \small\rm{ \dfrac{ \cancel{4228} \:  \: 2114}{ \cancel{2}}   = 7x}

  \rightarrow\small\rm{2114 = 7x}

 \rightarrow \small\rm{  \cancel\dfrac{2114}{7} = x }

  \rightarrow \small\sf{x = 302}

Length = 5x = 5 × 302 = 1510 cm

Breadth = 2x = 2 × 302 = 604 cm

 \rule{75mm}{2pt}

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