Question

LE
8. The sum of three consecutive multiples of 4 is 444. Find
these multiples.​

Answer 1

Step-by-step explanation:

let the sum of three consecutive multiples are x, x+4, x+8. therefore, algebraic expression. is x+(x+4)+(x+8)=444. 3x+12=444. 3x=444-12=432. 3x=432. x=432/3=144. x=144. the first consecutive number is =x=144. the second consecutive number is x+8=144+4=148 the third consecutive number is x+8=144+8=152

Answer 2

Answer :-

The three consecutive multiples of 4

which sums to 444 are 144, 148, 152.

Solution :-

Consider three consecutive multiples of 4 be x, (x + 4), (x + 8)

Sum of three consecutive multiples of 4 = 444

⇒ x + (x + 4) + (x + 8) = 444

Remove brackets

⇒ x + x + 4 + x + 8 = 444

⇒ 3x + 12 = 444

Transpose 12 to RHS

⇒ 3x = 444 - 12

⇒ 3x = 432

Transpose 3 to RHS

⇒ x = 432/3

⇒ x = 144

One multiple = x = 144

Second multiple = (x + 4) = (144 + 4) = 148

Third multiple = (144 + 8) = 152

Therefore the three consecutive multiples of 4 which sums to 444 are 144, 148, 152.

Verification :-

Let us check

x + (x + 4) + (x + 8) = 444

⇒ 144 + 148 + 152 = 444

⇒ 292 + 152 = 444

⇒ 444 = 444