LE
8. The sum of three consecutive multiples of 4 is 444. Find
these multiples.
Answers
Step-by-step explanation:
let the sum of three consecutive multiples are x, x+4, x+8. therefore, algebraic expression. is x+(x+4)+(x+8)=444. 3x+12=444. 3x=444-12=432. 3x=432. x=432/3=144. x=144. the first consecutive number is =x=144. the second consecutive number is x+8=144+4=148 the third consecutive number is x+8=144+8=152
Answer :-
The three consecutive multiples of 4
which sums to 444 are 144, 148, 152.
Solution :-
Consider three consecutive multiples of 4 be x, (x + 4), (x + 8)
Sum of three consecutive multiples of 4 = 444
⇒ x + (x + 4) + (x + 8) = 444
Remove brackets
⇒ x + x + 4 + x + 8 = 444
⇒ 3x + 12 = 444
Transpose 12 to RHS
⇒ 3x = 444 - 12
⇒ 3x = 432
Transpose 3 to RHS
⇒ x = 432/3
⇒ x = 144
One multiple = x = 144
Second multiple = (x + 4) = (144 + 4) = 148
Third multiple = (144 + 8) = 152
Therefore the three consecutive multiples of 4 which sums to 444 are 144, 148, 152.
Verification :-
Let us check
x + (x + 4) + (x + 8) = 444
⇒ 144 + 148 + 152 = 444
⇒ 292 + 152 = 444
⇒ 444 = 444