Question

Le bhai krr solve ab tu....


If tanA = cotB, prove that A+B = 90°.....​

Answer 1

Given

tanA = cotB

To prove

A + B = 90°

Proof

$\mathrm{\implies\:tanA = cotB}$

$\mathrm{\implies\:tanA = tan(90° - B) }$

| ∵ tan(90° - θ) = cotθ

$\mathrm{\implies\:\cancel{tanA}{ = \cancel{tan}(90° - B) }}$

$\mathrm{\implies\:A = 90° - B}$

| ∵ A and 90° - B are both acute angles

$\mathrm{\implies\:A + B = 90° }$

Hence proved

Answer 2

Step-by-step explanation:

tanA=cot(90-A)-----(1). [it's a trigonometric formula]

cotB=cot(90-A)----[given tanA=tanB]

B=90-A(cancelling cot)

A+B=90(proved)

good luck