Question

Le f(1) = 10, f(2)=50, f (3) = 70, f (4) = 80, f (y) = 10. The value of f(x) dx
using trapezoidal rule is​

Answer 1

Step-by-step explanation:

Let f(1) = 10, f(2)=50, f(3) =70, £ (4)$0, € (5) 10. The value of f f(x) dx using trapezoidal rule is

Answer 2

Answer: The value of $f(x)dx$ using the trapezoidal rule is 255

Step-by-step explanation:

• The trapezoidal rule is an integration rule which is used to calculate the area under a curve by dividing the curve into a number of small trapezoids.
• The summation of all the areas of these small trapezoids will give the area under the curve.

• Formula used=$\frac{h}{2}[(y_{0}+y_{n})+2( y_{2}+y_{2}+y_{3})]$

Step 1 of 1:

• Given Values:

     $x$           $y$

     1            10  

     2            50

     3            70

     4            80

     5            100

• take 10 as  $y_{0}$ ,50 as   $y_{1}$,70 as   $y_{2}$, 80 as   $y_{3}$, 100 as   $y_{4}$
• Put in formula

     $f(x)dx=\frac{h}{2}[(y_{0}+y_{n})+2( y_{2}+y_{2}+y_{3})]$

                 $=\frac{1}{2}[(10+100})+2( 50+70+80)]\\\\=\frac{1}{2}[110+400]\\=\frac{1}{2}[510]\\=255$

Conclusion:

Using the trapezoidal rule, the value of $f(x)dx$ is 255