Question

le sum of three consecutive integers is
twice the smallest of the integers. Find
the integers.​

Answer 1

Step-by-step explanation:

Let the three consecutive integers be n , n+1,n+2

so n+n+1+n+2=3n+3

From the data , 3n+3=2n. ( since n is the smallest integer)

So, 3n +3=2n

3n-2n+3=0

n+3=0

n=(-3)

The other two integers :-

n+1=(-3+1)=(-2)

n+2=(-3+2)=(-1)

ANSWER :- The three integers are (-3),(-2),(-1)

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Answer 2

Answer:

let three consecutive no are x,x+1,x+2

Step-by-step explanation:

x+(x+1)+(x+2)=3x+3

as per question

3x+3=2x

3x-2x=-3

x=-3

therefore three consecutive numbers are -3,-2,-1