Lead-202 has a half-life of 53,000 years. How long will it take for 15/16 of a sample of lead-202 to decay?
106,000 years
159,000 years
212,000 years
265,000 years
Answers
Answer:
212000 years
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Answer:
A radioactive substance's half-life is the amount of time it takes for half of the initial sample to decompose.
Explanation:
We can use the following algorithm to determine how long it will take for a particular portion of the sample to decay:
t = ln(N0/Nt) x (t1/2)
where N0 is the starting number of radioactive atoms, t1/2 is the half-life, and Nt is the final number of radioactive atoms.
Lead-202's half-life in this situation is listed as 53,000 years. We must ascertain the amount of time required for 15/16 of the material to decompose. This indicates that only 1/16 of the initial sample is still present. Nt/N0 therefore equals 1/16.
When we change the formula's provided numbers, we obtain:
t = x ln / (53,000 years)(16)
t = 265,000 years
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