Science, asked by madifletcher946, 5 months ago

Lead-202 has a half-life of 53,000 years. How long will it take for 15/16 of a sample of lead-202 to decay?

106,000 years
159,000 years
212,000 years
265,000 years

Answers

Answered by princess447
30

Answer:

212000 years

HOPE THIS WILL HELP YOU...... PLEASE MARK THIS AS BRAINLIEST AND FOLLOW ME.

Answered by syed2020ashaels
0

Answer:

A radioactive substance's half-life is the amount of time it takes for half of the initial sample to decompose.

Explanation:

We can use the following algorithm to determine how long it will take for a particular portion of the sample to decay:

t = ln(N0/Nt) x (t1/2)

where N0 is the starting number of radioactive atoms, t1/2 is the half-life, and Nt is the final number of radioactive atoms.

Lead-202's half-life in this situation is listed as 53,000 years. We must ascertain the amount of time required for 15/16 of the material to decompose. This indicates that only 1/16 of the initial sample is still present. Nt/N0 therefore equals 1/16.

When we change the formula's provided numbers, we obtain:

t = x ln / (53,000 years)(16)

t = 265,000 years

View more such questions :

https://brainly.in/question/3192175

#SPJ3

Similar questions