Question

Lead is fcc and its atomic radius is 0.175 nm. What is its volume, its face diagonal and its body
diagonal in the unit cell?

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Answer 1

Answer:

: (b) Lead Has FCC Structure And Its Atomic Radius Is 0.175 Nm. Calculate The Volume, Lengths Of Face Diagonal And Body Diagonal Of The Unit Cell

Explanation:

Answer 2

Answer:

Given We are given the radius of lead atom R 0.175 nm. We are asked to calculate the volume of the unit cell crystal structure of the lead Ve in cubic meters. Solution To calculate the volume of the unit cell we should know the crystal structure unit cell shape, where lead has FCC crystal structure (See Table 3.1) on page 54, where the volume of FCC crystal structure is given by equation 3.6 by Ve=16R3√2 (1) Now we can plug the vlaue for R in equation (1) to get Ve where R will be in (m) Vc=16R³√2 -16 (0.175 x 10-ºm)³√2 1.21 x 10-2 m 5.0 RESULT Vc = 1.21 x 10-28 m³