Question

lead is fcc and its atomic radius is 0.175nm.What is its unit cell edge length

Answer 1

Obtain the properties for lead, from table 3.1, “Atomic radii and crystal structures for 16 metals” as follows:

Atomic radii for lead 

Crystal structure of lead is FCC.

Since lead has an FCC crystal structure, obtain the relation for the volume of lead as follows:

Write the equation for unit cell length for FCC crystal structure.



Here, R is the atomic radius of lead.

Obtain the relation for the volume of the unit cell of the lead as follows:



Substitute  for.

 ……. (1)