Question

Lead spheres of diameter 6 cm are dropped into a cylindrical beaker containing some water and are fully submerged. If the diameter of the beaker is 18 cm and water rises by 40 cm. find the number of lead spheres dropped in the water.

Answer 1

Answer:

The number of lead sphere dropped in water is  90 .

Step-by-step explanation:

SOLUTION :  

Given :  

Diameter of a cylindrical beaker = 18 cm

Radius of the cylindrical beaker (R) = 18/2 =  9 cm

Height of  water in cylindrical beaker (h) = 40 cm

Diameter of a lead sphere = 6 cm

Radius of the lead sphere, r = 6/2 = 3 cm

Let the number of lead sphere be (n)

n = Volume of the cylindrical beaker/ Volume of the lead sphere

n = πR²h / 4/3πr³

n = R²h / 4/3r³

n = (9² × 40) / (4/3 × 3³)

n = (81 × 40 ) / ( 4 × 9)

n = 9 × 10 = 90  

n = 90

Hence,number of lead sphere dropped in water is  90 .

HOPE THIS ANSWER WILL HELP YOU….

Answer 2

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