Question

Lead spheres of diameter 6 cm each are dropped into a cylindrical beaker containing some water and get fully submerged.If the diameter of the beaker is 18 cm and the water level rises by 40 cm, find the number of lead spheres dropped in the water?​

Answer 1

Answer:

360 lead spheres.

Step-by-step explanation:

Radius of lead spheres=6/2=3cm

Volume of lead spheres=(4/3)π X 3³=$\frac{22 X 9}{7}$cm³

Let no. of lead spheres be $x$.

Total volume of lead shots=$\frac{22 X 9x}{7}$cm³

Volume of water rose in the beaker=π X 9² X 40 cm³

Total volume of lead shots=Volume of water rose in the beaker

$\frac{22 X 9x}{7}$cm³=π X 9² X 40 cm³

On solving, we get

$x$=360