Question

learning task 1 evaluate the following expressions using gemdas or pemdas rule.
$10 - 2 + 6 \div 3 = \\ (8 + 2) - (9 - {2}^{2} ) = \\ {3}^{2} - 15 \div 5 + (6 + 4) = \\ 5 + 2 - 3 = \\ 20 - 5 \times 4 + 1 = \\ 8 \times 2 - 4 \div 2 + 6 = \\ {( - 3)}^{2} - 6 + 3 = \\ 9 \times 8 - 36 \div 4 = \\ 3 + 2 + 8 \div (4 - 2) = \\ 16 - {6}^{2} + 36 =$
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Answer 1

Answer:

1.) 10 - 2 + 6 ÷ 3

 = 10 - 2 + 2

 = 8 + 2

 = 10

2.) (8 + 2) - (9 - 2²)

 = 10 - (9 -2²)

 = 10 - (9 - 4)

 = 10 - 5

 = 5

3.)3² - 15 ÷ 5 + (6 + 4)

= 3² - 15 ÷ 5 + 10

= 9 - 15 ÷ 5 + 10

= 9 - 3 + 10

= 6 + 10

= 16

4.)5 + 2 - 3

= 7 - 3

= 4

5.)20 - 5 × 4 + 1

= 20 - 20 + 1

= 0 + 1

= 1

6.) 8 × 2 - 4 ÷ 2 + 6

= 16 - 4 ÷2 + 6

= 16 - 2 + 6

= 14 + 6

= 20

7.) (3)² - 6 + 3

= 9 - 6 + 3

= 3 + 3

= 6

8.) 9 × 8 - 36 ÷ 4

= 72 - 36 ÷ 4

= 72 - 9

= 63

9.)3 + 2 + 8 ÷ 4 (4 - 2)

=3 + 2 + 8 ÷ 4 (2)

=3 + 2 + 8 ÷ 8

=3 + 2 + 1

=5 + 1

 =6

10.)16 - 6² + 36

 = 16 - 36 + 36

 = 20 - 36

= 16

Step-by-step explanation:

Answer 2

Answer:

By using gemdas or pemdas rule the answers of the equations are,

1. 10

2.5

3.16

4. 4

5. 1

6. 20

7.  6

8. 63

9. 6

10. 16

Step-by-step explanation:

PEMDAS stands for an acronym utilized to mention the order of procedures to be observed while solving expressions having multiple functions. PEMDAS stands for P- Parentheses, E- Exponents, M- Multiplication, D- Division, A- Addition, and S- Subtraction.

Order of operations is a collection of practices to perform operations in an arithmetic expression. There are various methods where everything reaches through different phases in a fixed sequence

By using the rile the answers are as follows,

1.

$10-2+6 \div 3$

$&=10-2+2$

$&=8+2$

$=10$

2.

$(8+2)-\left(9-2^{2}\right)$

$=10-\left(9-2^{2}\right)$

$=10-(9-4)$

$=10-5$

$=5$

3.

$3^{2}-15 \div 5+(6+4)$

$=3^{2}-15 \div 5+10$

$=9-15 \div 5+10$

$&=9-3+10$

$&=6+10$

$&=16$

4.

$} 5+2-3$

$&=7-3$

$&=4$

5.

$20-5 \times 4+1$

$&=20-20+1$

$&=0+1$

$&=1$

6.

$8 \times 2-4 \div 2+6$

$&=16-4 \div 2+6$

$&=16-2+6$

$&=14+6$

$=20$

7.

$(-3)^{2}-6+3$

$(3)^{2}-6+3$

$=9-6+3$

$=3+3$

$=6$

8.

$9 \times 8-36 \div 4$

$=72-36 \div 4$

$=72-9$

$=63$

9.

$3+2+8 \div 4(4-2)$

$&=3+2+8 \div 4(2)$

$&=3+2+8 \div 8$

$&=3+2+1$

$&=5+1$

$&=6$

10.

$16-6^{2}+36$

$&=16-36+36$

$&=20-36$

$&=16$

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