Math, asked by nikkoleselleza, 3 months ago

Learning Task 3: Solve the following. Do this in a separate sheet of paper.
1. A box is (2x-3) by (x + 5) by ( 3x +1), what is the volume of the box if x = 3 cm?
2. The formula for the area of a triangle is A = if the base (b) = 10 cm and the height (h) = 6 cm, what is
the area of the triangle?
3. The length (l) of the rectangle is x2 + 2x-3 and the width (w) is 5x +4, what is the perimeter of the rectangle.
4. From the sum of 3x + 7x? - S and 2x2 + 3x + 8 take away 5x+x-5.
5. What should be added to 3x3 + 4x2-7 to have a sum of 4x + 2 5​

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Answers

Answered by annudahiya
78

your answer is in the pic

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Answered by amitnrw
24

Given :   A box is (2x-3) by (x + 5) by ( 3x +1),

To Find  :  volume of the box if x = 3 cm

Solution:

box is (2x-3) by (x + 5) by ( 3x +1),

=> Volume of Box = (2x - 3)(x + 5)(3x + 1)

x = 3

=> Volume of Box = ( 2(3) - 3) (3 + 5) ( 3(3) + 1)

= ( 6 - 3)(8)(9 + 1)

= 3(8)(10)

= 240 cm³

Area of triangle = (1/2)bh

= (1/2)* 10 * 6

=  30 cm²

length (l) of the rectangle is x² + 2x-3

width (w) is 5x +4,  

Perimeter = 2 ( l + w)

= 2( x² + 2x-3 + 5x + 4)

= 2( x² + 7x + 1)

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