Question

Learning Task 4: Do it in your notebook.
A. Describe the slope and y-intercepts of the graphs of the system of equations.
​

Answer 1

Answer:

Sa tuwing ika'y pinagmamasdan

Tila ba'y umuusbong ang kasiyahan

Nawawala ang kalumbayan

At naiisip ang bagong yugto na tayo'y magkasintahan

Answer 2

The slopes and y-intercepts of the given graphs are as follows -

• 1. Line(1) - Slope = $\frac{y2-y1}{x2-x1}$ = $\frac{3-0}{0-6}$ = $\frac{-1}{2}$, y-intercept = 3 ; Line(2) - Slope = $\frac{y2-y1}{x2-x1}$ = $\frac{7-0}{0-(-5)}$ = $\frac{7}{5}$, y-intercept = 7.
• 2. Line(1) - Slope = $\frac{y2-y1}{x2-x1}$ = $\frac{-3-0}{0-2}$ = $\frac{3}{2}$, y-intercept = -3 ; Line(2) - Slope = $\frac{y2-y1}{x2-x1}$ = $\frac{5-0}{0-(-3)}$ = $\frac{5}{3}$, y-intercept = 5.
• 3. Line(1) - Slope = $\frac{y2-y1}{x2-x1}$ = $\frac{4-0}{0-1}$ = -4, y-intercept = 4 ; Line(2) - Slope = $\frac{y2-y1}{x2-x1}$ = $\frac{-4-0}{-9-0}$ = $\frac{4}{9}$, y-intercept = -4.
• 4. Line(1) - Slope = $\frac{y2-y1}{x2-x1}$ = ∞, no y-intercept ; Line(2) - Slope = $\frac{y2-y1}{x2-x1}$ = $\frac{3-0}{0-6}$ = $\frac{-1}{2}$, y-intercept = 3.
• 5. Line(1) - Slope = $\frac{y2-y1}{x2-x1}$ = $\frac{4-0}{0-2}$ = -2, y-intercept = 4 ; Line(2) - Slope = $\frac{y2-y1}{x2-x1}$ = $\frac{-1-0}{0-\frac{1}{2} }$ = 2, y-intercept = -1.

#SPJ3