Question

learning task 4:Solve the problem involving systems of linear equations in two variables.​

Answer 1

Answer:

this may be easy for you

first you imagine the question

and then answer

it may be easy to complete

Answer 2

Answer:

The mother bought 10 kg of mangoes and 10 kg of atis.

Step-by-step explanation:

a) Price of mango = Rs. 60 per kg

Price of atis = Rs. 40 per kg

Combined quantity = 20 kg.

Let x be the number of mangoes.

Atis = 20 - x

ATQ:

60 x + 40(20 - x) = 1000

60 x + 800 - 40 x = 1000

20 x = 200

x = 200 / 20

x = 10.

So, mother bought 10 kg of mangoes and 10 kg of atis.

Now, also let the number of atis be y.

So, the equation will become:

x + y = 20.

b) Equation for the cost of fruits will be:

60 x + 40 y = 1000

c) The system of equations are:

x + y = 20 and 60 x + 40 y = 1000

d) We know that:

y = 20 - x

Put it another equation:

60 x + 40 (20 - x) = 1000

60x + 800 - 40 x = 1000

20 x = 200

x = 10 kg

y = 20 - x

y = 20 - 10

y = 10 kg

e) Check:

60 (10) + 40 ( 10) = 1000

600 + 400 = 1000

1000 = 1000

since LHS = RHS, it is correct.

Therefore, we get that the mother bought 10 kg of mangoes and 10 kg of atis.

#SPJ3