Leas house is 350 meters from her friends house. Lea walks to her friends house at a constant rate of 50 meters per minute . What equation expresses the relationship between time and the distances Lea has left to wall to her friend's house .
A. Y=350 -50x
B. Y = 350x - 50
C. Y = 50x + 350
D. Y = 50x - 350
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Step-by-step explanation:
At first divide 350 by 50
350/50= 7
on this way we calculated how much minute she has to walk to the friends house with constant rate of 50 meters per minute as we have five fields in the table for values of time and distance , divide 7 by 5
7.0/5= 1.4
the value of distance for each value of time in table we calculate. as
distance = 50 time
time(min). 1.4. 2.8. 4.2. 5.6. 7
distance. 70 140. 210. 280 350
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