Math, asked by 4081322, 3 months ago

Leas house is 350 meters from her friends house. Lea walks to her friends house at a constant rate of 50 meters per minute . What equation expresses the relationship between time and the distances Lea has left to wall to her friend's house .
A. Y=350 -50x
B. Y = 350x - 50
C. Y = 50x + 350
D. Y = 50x - 350

Answers

Answered by k345815
1

Step-by-step explanation:

At first divide 350 by 50

350/50= 7

on this way we calculated how much minute she has to walk to the friends house with constant rate of 50 meters per minute as we have five fields in the table for values of time and distance , divide 7 by 5

7.0/5= 1.4

the value of distance for each value of time in table we calculate. as

distance = 50 time

time(min). 1.4. 2.8. 4.2. 5.6. 7

distance. 70 140. 210. 280 350

Similar questions