Lease solve this question
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Answered by
2
Answer:
let line AB and DE meet at point Z
<ABC = <BZE ( corresponding angles) ...........1
<BZE = <EDF ( alternative interior angles) .......2
from equation 1 and 2
< ABC = < EDF
hence proved
Answered by
0
Answer:
same as this question
Step-by-step explanation:
fig. is mostly same as yours
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