Question

least common multiple 12 and 80


please answer l gave you point. ​

Answer 1

Given: The numbers are $12$and$80$.

We have to find the least common multiple of $12$and$80$.

We are solving in the following way:

The Prime Factorization of $12$ is:

=> $2\times2\times3=2^{2} \times 3^{1}$

The Prime Factorization of $80$ is:

=>$2 \times 2 \times 2 \times 2 \times 5 => 2^{4} \times 5^{1}$

Now for each prime factor, we will find where it occurs most often as a factor and write it that many times in a new list.

The new superset list is:

$2, 2, 2, 2, 3, 5$

Multiplying these factors together to find the LCM:

LCM:

$=> 2 \times 2 \times 2 \times 2 \times 3 \times 5 \\=>240$

Hence,  LCM of $(12, 80) = 240$

Answer 2

Correct answer:-

Given: The numbers are 1212 and 8080.

We have to find the least common multiple of 1212 and 8080.

We are solving in the following way:

The Prime Factorization of 1212 is:

=> 2\times2\times3=2^{2} \times 3^{1}2×2×3=2

2

×3

1

The Prime Factorization of 8080 is:

=>2 \times 2 \times 2 \times 2 \times 5 = > 2^{4} \times 5^{1}2×2×2×2×5=>2

4

×5

1

Now for each prime factor, we will find where it occurs most often as a factor and write it that many times in a new list.

The new superset list is:

2, 2, 2, 2, 3, 52,2,2,2,3,5

Multiplying these factors together to find the LCM:

LCM:

\begin{gathered}= > 2 \times 2 \times 2 \times 2 \times 3 \times 5 \\= > 240\end{gathered}

=>2×2×2×2×3×5

=>240

Hence, LCM of (12, 80) = 240(12,80)=240.

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