Math, asked by adjain1902, 7 months ago

least distance between two points p and q on circles x2 + y2 + 14x - 4y + 28 and x2 + y2 - 14x + 4y + 28

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Answered by Anonymous

Answer:

using perpendicular distance formula from centre to ... Example 5: From a point P tangents are drawn to circles x2 + y2 + x – 3 ... Q.21 The equation of a circle C1 is x2+y2+14x–4y + 28=0 .

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least distance between two points p and q on circles x2 + y2 + 14x - 4y + 28 and x2 + y2 - 14x + 4y + 28​

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least distance between two points p and q on circles x2 + y2 + 14x - 4y + 28 and x2 + y2 - 14x + 4y + 28