least number of meiotic division to form 120 seeds in angiosperms
150
121
30
120
Answers
Answered by
21
Given:
Total number of seeds= 120
To find:
Least number of meiotic divisions required
Solution:
Seeds are generated by the fusion of male and female gametes. So, for producing 120 seeds, we require 120 male gametes and 120 female gametes.
Firstly, for male gametes:
1 meiotic division refers to the formation of 4 microspores from one microspore mother cell. Each microspore develops into a pollen grain( male gamete).
So, for getting 120 male gametes, we require= 120/4 = 30 meiotic divisions.
Secondly, for female gametes:
One female gamete is produced by one megaspore mother cell.
So, for getting 120 female gametes, we require 120 meiotic divisions.
Therefore, the total number of meiotic divisions required= 30+120= 150.
The least number of meiotic divisions to form 120 seeds in angiosperms is 150.
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