Question

least number of meiotic division to form 120 seeds in angiosperms
150
121
30
120

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Answer 1

Given:

Total number of seeds= 120

To find:

Least number of meiotic divisions required

Solution:

Seeds are generated by the fusion of male and female gametes. So, for producing 120 seeds, we require 120 male gametes and 120 female gametes.

Firstly, for male gametes:

1 meiotic division refers to the formation of 4 microspores from one microspore mother cell. Each microspore develops into a pollen grain( male gamete).

So, for getting 120 male gametes, we require= 120/4 = 30 meiotic divisions.

Secondly, for female gametes:

One female gamete is produced by one megaspore mother cell.

So, for getting 120 female gametes, we require 120 meiotic divisions.

Therefore, the total number of meiotic divisions required= 30+120= 150.

The least number of meiotic divisions to form 120 seeds in angiosperms is 150.