Question

Least number which when divided by 24 , 16 20 leaves remainder 20 12 16 respectively

Answer 1

Least number which when divided by 24, 16, and 20 leaves the remainder 20 12, and 16 respectively is 236

We solve this problem by using the least common multiple (LCM) of 24, 16, and 20

LCM(24, 16, 20) = 240

We have been given that x, when divided by 24, 16, and 20 leaves remainders 20, 12, and 16 respectively

From this, we can see that there is a common difference of 4 between the divisors and the reminders, that is

24 - 20 = 4,
16 - 12 = 4, and
20 - 16 = 4

Now, we can see that 240 - 4 = 236.

Therefore,

240 - 24 + 20 = 236
240 - 16 + 12 = 236
240 - 20 + 16 = 236

Hence, the required number = 236

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