Question

Least value that *can take to ensure that 451*603 is exactly divisible by 9

Answer 1

4+5+1+x+6+0+3=multiple of9
19+x=27(nearest multiple)
x=27-19=8
least value of x is 8

Answer 2

Least value that * can take to ensure that 451*603 is exactly divisible by 9 is 8

Given :

451*603 is exactly divisible by 9

To find :

Least value that * can take to ensure that 451*603 is exactly divisible by 9

Concept :

Divisibility rule of 9 :

A number is divisible by 9 if the sum of its digits is divisible by 9

Solution :

Step 1 of 2 :

Write down the given number

Here the given number is 451*603

Step 2 of 2 :

Find the digit at *

Let the digit at * is n

Then the number becomes 451n603

Sum of the digits

= 4 + 5 + 1 + n + 6 + 0 + 3

= n + 19

Since the number 451n603 is divisible by 9

∴ n + 19 is divisible by 9

Since n is one digit

∴ n = 8

Hence least value that * can take to ensure that 451*603 is exactly divisible by 9 is 8

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