Leaving home at the same time, if Pratibha walks to
school at 3 km/h, she reaches 10 min late. If she cycles
to school at 6 km/h, she reaches 15 min early. How far
is the school from her home?
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1
Answer:
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Answered by
3
Answer:
let time=X
distance=y
A.T.Q
3*(x+10)=y
3x+30=y
3x-y=30
x=30+y/3
6*(x-15)=y
6x-90=y
6(30+y/3)-90=y
60-90+2y=y
2y-y=30=y
distance=30km
Step-by-step explanation:
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