Question

Leaving howrah station after 1 hr a train is late by 1 hr for special reason and then running with 3/5th of its initial speed it reaches its destination after 3 hours if the special reason would be 50km away from its first place then the train would reach its destination 1hr 20 mins before its previous time. Calculate the distance and speed
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Answer 1

Answer:

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A ____100 km____ P1 ________300 km_____ P2 ____X______ B

If speed becomes 5 / 6   then time taken will be 6 / 5  of original time.

Thus, extra time = 2 hour

1 / 5  = 2 hour

Thus unusual time which is require to complete the journey = 5 × 2 = 10 hours.

It means It covers 300 km distance in 5 hours.

Then speed = 300 / 5   = 60 km/h

Thus the speed of the train is 60 km/h