leena bent a wire 132cm long into a square. what is the length of a side of a sqaure
Answers
Answer:
Question:
In the adjacent Quadrilateral ABCD, AC is the diagonal of length 36cm, BE and DF perpendicular from B and D to AC are 8cm and 12cm respectively. Find the area of the quadrilateral.
Answer:
Area of the given Quadrilateral = 860 cm²
Step-by-step explanation:
In the given figure we have two triangles, ∆ADC and ∆ABC.
The ∆ ADC, Base = 36cm and height = 12cm
Now, let's calculate the area of the ∆ ADC
\bf Area \ of \ \triangle ADC = \dfrac{1}{2} BASE \times HEIGHTArea of △ADC=
2
1
BASE×HEIGHT
\sf Area \ of \ \triangle ADC = \dfrac{1}{2} 36 \times 12Area of △ADC=
2
1
36×12
\sf Area \ of \ \triangle ADC = 18 \times 12Area of △ADC=18×12
\sf Area \ of \ \triangle ADC = 216cm^2Area of △ADC=216cm
2
The ∆ ABC, Base = 36cm and Height = 8cm
Now, let's calculate the area of the ∆ ABC
\bf Area \ of \triangle ABC = \dfrac{1}{2} BASE \times HEIGHTArea of△ABC=
2
1
BASE×HEIGHT
\sf Area \ of \ \triangle ABC = \dfrac{1}{2} 36 \times 8Area of △ABC=
2
1
36×8
\sf Area \ of \ \triangle ABC = 36 \times 4Area of △ABC=36×4
\sf Area \ of \ \triangle ABC = 144cm^2Area of △ABC=144cm
2
Area of Quadrilateral = ADC + ABC
Area of Quadrilateral = 216cm² + 144cm² = 360cm²