Question

Leena has 117 rupees in the form of 5 rupee coins and 2 rupee coins. The number of 2 rupee coins is 4 times that of 5 rupees coins. Find the number of coins of each denominator.​

Answer 1

Answer:

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Step-by-step explanation:

Number of 5rs coin = x

number of 2rs coins = 4x

total money = 5*x + 4x * 2 = 5x+8x = 13x

13x = 117

x = 117/13 = 9

number of 5rs coins= x = 9

number of 2rs coins = 4x = 4*9 = 36

Answer 2

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$\huge{\underline{\underline{\sf{\blue{SOLUTION:-}}}}}$

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$\sf{\underline{\green{AnswEr:-}}}$

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• Number of 5 rupees coin = 9

• Number of 2 rupees coin = 36

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$\sf{\underline{\green{Given:-}}}$

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• Leena has 117 rupees in the form of 5 rupee coins and 2 rupee coins. The number of 2 rupee coins is 4 times that of 5 rupees coins.

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$\sf{\underline{\green{Find:-}}}$

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• Number of 5 rupees coin = ?

• Number of 2 rupees coin = ?

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$\sf{\underline{\green{Explanation:-}}}$

Let 5 rupees coin be y.

$\:\:\:\:\dag\bf{\underline{\underline \red{Then:-}}}$

• 2 rupees coin = 4y

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$\sf{\underline\pink{A.T.Q:-}}$

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$\longrightarrow \sf {y \times 5 + 4y \times 2 = 117}$

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$\longrightarrow \sf {5y + 8y = 117}$

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$\longrightarrow \sf {13y = 117}$

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$\longrightarrow \sf {y = \cancel\dfrac{117}{13} }$

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$\longrightarrow \sf {y = 9}$

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$\:\:\:\:\dag\bf{\underline{\underline \red{Hence:-}}}$

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• Number of 5 rupees coin is 8.

• Number of 2 rupees coin = 4 × 9
• Number of 2 rupees coin is 36.

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$\rule{200}{2}$