Question

leena has 117 rupees in the form of 5 rupees and 2 rupee coins. the number of 2 rupee coins is 4 times of 5 rupee coins. find the number of coins of each demonations​

Answer 1

✬ 2 rupee coins = 36 ✬

✬ 5 rupee coins = 9 ✬

Step-by-step explanation:

Given:

• Total money she has Rs 117 in form of 5 rupees and 2 rupees.
• Number of 2 rupee coins is 4 times the number of 5 rupee coins.

To Find:

• Number of coins of each type ?

Solution: Let the number of 5 rupees coins be Rs x. Therefore,

➟ Number of 2 rupee coins = 4 times of x

➟ 2 rupee coins = Rs 4x

A/q

• 2 rupee coins + 5 rupee coins = total amount
• 2 × 4x + 5 × x = 117

$\implies{\rm }$ 8x + 5x = 117

$\implies{\rm }$ 13x = 117

$\implies{\rm }$ x = 117/13

$\implies{\rm }$ x = 9

So number of coins

• 5 rupee coins = x = 9
• 2 rupee coins = 4x = 4(9) = 36

[ Verification ]

➨ 9 × 5 + 36 × 2 = 117

➨ 45 + 72 = 117

➨ 117 = 117

$\large\bold{\texttt {Verified }}$

Answer 2

Given :

• Leena has 117 rupees in the form of 5 rupees and 2 rupee coins. the number of 2 rupee coins is 4 times of 5 rupee coins.

　

To find :

• What is the number of coins of each denomination.

　

According to the question :

• Let us assume "x" as the number of 5 rupees coin and "4x" as number of 2 rupees coin.

　

Calculations :

→ 117 = (2 × 4x) + (5 × x)

→ 117 = 8x + 5x

→ 117 = 13x

→ x = 117/13

→ x = 9 [5₹ coins]

　

→ 9 (4)

→ 36 [2₹ coins]

　

Therefore, number of five rupees coin is 9 and number of two rupees coin is 36.