Question

Leena's father is thrice as old as Leena.After 12 years he will just twice his daughter.Find their present ages.

Please answer it fast....
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Answer 1

Answer:

Step-by-step explanation:

let leena's age be x

fathers age = 3x

leena's age after 12 years = x+12

fathers age after 12 years = 3x+12

3x+12=2*x+12

3x-2x=24-12

x=12

Leena's age = 12 years

Her fathers age = 3*12= 36 years

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Answer 2

Answer:

We know that : \sf{\sin\theta = Opposite\:Side/Hypotenuse}sinθ=OppositeSide/Hypotenuse

\longrightarrow\sf{a/b = Opposite\:Side/Hypotenuse}⟶a/b=OppositeSide/Hypotenuse

\bigstar★ From this Information ;

\longrightarrow⟶ Opposite Side = a \&& Hypotenuse = b

Step-by-step explanation:

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