Math, asked by priyanshuverma672003, 4 months ago


Leena's mother is four times as old as Leena. After five years her mother will be three times as old as she will
be then. What are their present ages?

Answers

Answered by priyanshukumawat30
7

Answer:

let Leena's age be x

so her mother's age will be 4x

After five years

x+5 and 4x+5

so according to the question

3(x+5)=4x+5

3x+15=4x+5

4x-3x=15-5

x=10

Leena's age is 10 years

therefore her mother's age is 4x

4×10=40 years

Answered by monoranjanbl
5

Leena's age=X

Lenna's mother's age =4X

five years after....

Leena's age=X+5

Leena's mother's age=4X+5

therefore,4X+5=3(X+5)

4X+5=3X+15

4X-3X=15-5

X=10

therefore

Leena's age=X=10

Leena's mother's age=4X=4×10=40

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