Math, asked by Atul8664, 1 day ago

Left Raipur at 6:00 a.m. and stopped in between for 30 minutes it reaches Nagpur at 6:30 pm on the same day if the total distance covered by the bus is 300 find the speed of the bus

Answers

Answered by anshulriyanshi
0

Answer:

25 km per hour

Step-by-step explanation:

He left Raipur at 6:00 a.m.

Reached Nagpur at 6:30 p.m.

Break of 30 mins

He reached Nagpur 12 hrs 30 mins after leaving Raipur.

But there is a break and that will not help us calculate the speed.

So remove the time.

So 12 hrs 30 min - 30 mins = 12 hrs

Given information → the bus travels 300 km

According to us the bus travel 300 km in 12 hrs

Speed = \frac{Distance}{Time}

So here, Speed = \frac{300}{12}

⇒ Speed = 25 km per hour

If you want it in meters per second,

Speed(in kmph) × \frac{5}{18} is the formula.

Here, 25 kmph × \frac{5}{18} = \frac{125}{18} m per sec or 6.94 m per sec

If you want in metres per minute,

Speed(in kmph) × \frac{50}{3} is the formula.

Here, 25 kmph × \frac{50}{3} = \frac{1250}{3} m per min or 416.66 m per min.

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