Question

lenght of a rectangle, if it's perimeter =32cm and width =5cm

Answer 1

Answer:

$\huge{\fcolorbox{black}{red}{\blue{question}}}$

find the length of a rectangle, if it's perimeter is 32cm and width is 5cm.

${\fcolorbox{black}{pink}{\green{solution}}}$

$\underline\bold\red{length\:=\:11cm}$

${\fcolorbox{black}{orange}{\purple{let's \:find \:out}}}$

$\underline\mathfrak\pink{using\:formula}$

$\underline\blue{perimeter \:of \:rectangle \:is\: 2(l+b)}$

$\pink{given:-}$

• $\green{perimeter\:=\:32cm}$
• $\green{length\:=\: l}$
• $\green{width\:=\:5cm}$

$\purple{so,}$

$= > 2(l + 5) = 32$

$= > 2l + 10 = 32$

$= > 2l = 32 - 10$

$= > 2l = 22$

$= > l = \frac{22}{2}$

$= > l = 11$

hence the length of the rectangle is 11cm.

____________________**___________________

• perimeter of square = 4(sides)
• perimeter of rectangle = 2(l+b)
• perimeter of triangle = a+b+c

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Answer 2

Hope it helps uh mate. . . . . . .