Question

lenght of a room is 9m and it`s breath is 6cm . find the numbers of tiles requierd to pave the floor , if the side of 1 sqare tile is 0.75m

Answer 1

Step-by-step explanation:

Area of floor when length = 9m and Breadth = 6 cm

Now new length = 9×100cm = 900cm

$area \: of \: floor \: = (length \times breath)$

$area \: of \: floor \: = (900 \times 6)cm ^{2} \\ ∴area \: of \:floor \: = 5400 {cm}^{2}$

Now area of tile when length of side 0.75cm

$area \: of \: tile = {a}^{2}$

$area \: of \: tile \: = {0.75}^{2}$

$area \: of \: tile\: = 0.5625m ^{2}$

Here area of tile is in m^2

we have to change it in cm^2

∴ We know that 1m^2=1000cm^2

so , 0.5625m^2=5625cm^2

So no. of tiles required

= area of floor÷area of tile

5400÷5625

= 0.96 Answer