Question

length(2x+9)m and dreadth(3x+5)m. find the area ?

Answer 1

$length = (2x + 9)m \\ breadth = (3x + 5)m \\ \\ area = length \times breadth \\ = (2x + 9) \times (3x + 5) \\ = (6 {x}^{2} + 10x + 27x + 45) \\ = (6 {x}^{2} + 37x + 45) {m}^{2}$

Answer 2

Length of the rectangle = ( 2x + 9 ) m


Breadth of the rectangle = ( 3x + 5 ) m




Area of the rectangle = length × breadth


Area of the rectangle = ( 2x + 9 ) ( 3x + 5 ) m²


Area of the rectangle = 2x( 3x + 5 ) + 9( 3x + 5 ) m²


Area of the rectangle = 6x² + 10x + 27x + 45 m²


Area of the rectangle = 6x² + 37x + 45 m²



Therefore the area of the. rectangle is 6x² + 37x + 45 m²

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