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3. How many tiles are required to cover a floor of length 6 m and breadth 4m
if the area covered by each tile is 400 sq. cm?
Answers
Answered by
2
Answer:
600 tiles.
Explanation:
6 m= 6×100 cm
=600 cm
Similarly, 4m=400 cm
Area of the floor= 600×400 cm²
= 240000 cm²
Number of tiles= Area of floor/Area of one tile
= 240000/400
= 600 tiles
Therefore, 600 tiles are required.
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Answered by
0
Explanation:
Given:Length=6m
Breadth=4m
Area of rectangle=L×B
=6×4
=24m
Therefore 24×100
=2400cm
Therefore 2400÷400
=6
Therefore for covering floor six tiles will be required.
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