Question

length 3x^2y+y^2 breadth 5/8x^2 . find the area​

Answer 1

Answer:

Given,

Length, l =  $3x^2y + y^2$

Breadth, b =  $\frac{5}{8}x^2$

Area = Length  ×  Breadth

        = l  ×  b

        $= ( 3x^2y + y^2)$ × $(\frac{5}{8}x^2)$

        $= 3x^2y * \frac{5}{8}x^2 + y^2 * \frac{5}{8}x^2$

        $= \frac{15}{8}x^4y + \frac{5}{8}x^2y^2$

        $=\frac{x^2y}{8}(15x^2 + 5y)$

          Hope it helps you^_^