length 55mm and breadth 4cm
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0
Answer:
Draw a rectangle PQRS in the given measurement. PQ produced up to T as QT=3cm. Draw a perpendicular bisector of the lime PT, meet Q on PT. Produce QR meet the semicircle at M. Draw the square QMNO as QM
=MN=ON=QO. Hence QMNO be the required square.
solution
Answered by
1
Answer:
per= 2(l+b)
= 2(55+4)
2*59
= 118
area = l*b
55*4
answer is 220
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