Length & breadth of the path was 22m and 14m.Find the area of the path which is of uniform width 1.9m inside the rectangle.
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l = 22m
b = 14m
area of park = l*b = 22*14
= 308
width of path = 1.9m
new l = 22-1.9 = 20.1m
new b = 14-1.9 = 12.1m
new area = l*b = 20.1*12.1=243.21m
area of path = area of park - area of new park
= 308-243.21
=64.79m^2
b = 14m
area of park = l*b = 22*14
= 308
width of path = 1.9m
new l = 22-1.9 = 20.1m
new b = 14-1.9 = 12.1m
new area = l*b = 20.1*12.1=243.21m
area of path = area of park - area of new park
= 308-243.21
=64.79m^2
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