Question

Length & breadth r in ratio 7:4 & perimeter = 110 m. Find -
1. Area of floor of hall.
2. No. Of tiles ,each size
25cm×20cm, required for
flooring hall.
3. Cost of tiles at rate of Rs 1400 per hundred tiles.

Answer 1

Length= 7x
Breadth= 4x
Perimeter= 110 m
Perimeter= 2(length+breadth)
110= 2(7x+4x)
110= 2×11x
110= 22x
x=110/22
x=5
Therefore, length= 35m
Breadth= 20m
Area of the hall= l×b
35×20 m^2
700m^2
Now,
Area= 700m^2= 700×10000= 7×10^6 cm^2
Area of 1 tile= 25×20= 500 cm^2
No. of tiles required= ar. of hall/ar. of 1 tile
= 7000000/500 cm^2/cm^2
= 14000
Cost of tiles at rate of Rs 1400 per hundred tiles= 14000/100×1400= Rs. 196000

Answer 2

let the length of the Hall=7x
breath of the hall=4x


perimeter of the hall=2 (l+b)

110=2 (7x+4x)

110=2 (11x)

110=22x

22x=110

x=5

length=7×5=35m

breadth=4×5=20m

2)area of hall=l×b

=35×20=700m^2

Area occupied by one tite=l×b of tile =25×20=500

no.of tiles=700÷500=1.4

cost of flooring 1.4 tiles=500×1.4×1÷100=rs.7
ans


hope its helps